A hollow sphere of mass m and radius r is rolling downward

- The moment of inertia of a
**sphere**about an axis through its centre is (2/5) MR 2 and that of a thin- walled**hollow sphere of mass m and radius R**is (2/3) mR². 7.) A**mass m**is attached to a weightless string of length L, cross section S and tensile strength T. The**mass**is suddenly released from a point near the fixed end of the string. **A**solid uniform**sphere****of****mass**,**M****and****radius**,**R****is**placed on an inclined plane at a distance, h from the base of the incline. The inclined plane makes an angle, θ with the horizontal. The**sphere****is**released from rest and rolls down the incline without slipping. The moment of inertia of the**sphere****is****I**= 2 5 MR2.**A**solid**sphere**(**I**= (2/5)MR^2) and a solid cylinder (**I**= (1/2)MR^2) of the same**mass****and****radius**roll without slipping at the same speed.It is correct to say that the total kinetic energy of the solid**sphere****is****a**. impossible to compare to the total kinetic energy of the cylinder.b. more than the total kinetic energy of the cylinder. When a body rolls on a horizontal surface without slipping the ...- The
**rolling**object's downhill acceleration is smaller by a factor 1 1 + I mR2! I = mR2 for**hollow**cylinder. 1 1+1 = 0:5 I = 2 3 mR 2 for**hollow****sphere**. 1 1+(2=3) = 0:60 I = 1 2 mR 2 for solid cylinder. 1 1+(1=2) = 0:67 I = 2 5 mR 2 for solid**sphere**. 1 1+(2=5) = 0:71 Using Chapter 11 ideas, we know how to analyze the**rolling**objects' motion ... **A****hollow****sphere****of****mass****M****and****radius****R****is**sliding with a velocity v o at the top of a frictionless tabletop between point A and B. Then it enters a rough section of the tabletop - point B. As the**sphere**moves through the rough section the friction force changes its motion from sliding to**rolling**.